[tex]Zadanie\\\\\frac{2x^{2} -5x+6}{2-3x}\ \ \ \ \ dla\ x=-2\\\\\frac{2\cdot(-2)^{2} -5\cdot(-2)+ 6}{2-3\cdot(-2)}=\frac{2\cdot4+10+6}{2+6}=\frac{8+16}{8}=\frac{24}{8}=3[/tex]
