[tex]dane:\\m = 10 \ kg\\Q = 1 \ 800 \ J\\T_1 = 10^{o}C\\T_2 = 70^{o}C\\\Delta T = T_2 - T_1 = 70^{o}C - 10^{o}C = 60^{o}C\\szukane:\\c = ?\\\\c = \frac{Q}{m\cdot\Delta T}\\\\c = \frac{1800 \ J}{10 \ kg\cdot60^{o}C}\\\\c = 3\frac{J}{kg\cdot^{o}C}[/tex]
