Odpowiedź:
[tex]d=a\sqrt{2}\\\\10=a\sqrt{2} /:\sqrt{2}\\\\a=\frac{10}{\sqrt{2} }[/tex]
[tex]\frac{10}{\sqrt{2} } *\frac{\sqrt{2} }{\sqrt{2} } =\frac{10\sqrt{2}}{\sqrt{2} \sqrt{2} } =\frac{10\sqrt{2} }{2} =5\sqrt{2}[/tex]
Odp. Bok tego kwadratu ma dlugosc [tex]5\sqrt{2}cm[/tex]
