Odpowiedź :
[tex]1.08 \div (-0.4)-2 \frac{ 5 }{ 6 } \div 1.7-2 \frac{ 1 }{ 2 } \times (1.4-1 \frac{ 4 }{ 5 } )-(- \frac{ 7 }{ 15 } )=\frac{108}{-40}-\frac{\frac{2\times 6+5}{6}}{1.7}-\frac{2\times 2+1}{2}\left(1.4-\frac{1\times 5+4}{5}\right)-\left(-\frac{7}{15}\right) = -\frac{27}{10}-\frac{\frac{2\times 6+5}{6}}{1.7}-\frac{2\times 2+1}{2}\left(1.4-\frac{1\times 5+4}{5}\right)-\left(-\frac{7}{15}\right) = -\frac{27}{10}-\frac{2\times 6+5}{6\times 1.7}-\frac{2\times 2+1}{2}\left(1.4-\frac{1\times 5+4}{5}\right)-\left(-\frac{7}{15}\right) = -\frac{27}{10}-\frac{12+5}{6\times 1.7}-\frac{2\times 2+1}{2}\left(1.4-\frac{1\times 5+4}{5}\right)-\left(-\frac{7}{15}\right) = -\frac{27}{10}-\frac{17}{6\times 1.7}-\frac{2\times 2+1}{2}\left(1.4-\frac{1\times 5+4}{5}\right)-\left(-\frac{7}{15}\right) = -\frac{27}{10}-\frac{17}{10.2}-\frac{2\times 2+1}{2}\left(1.4-\frac{1\times 5+4}{5}\right)-\left(-\frac{7}{15}\right) = -\frac{27}{10}-\frac{170}{102}-\frac{2\times 2+1}{2}\left(1.4-\frac{1\times 5+4}{5}\right)-\left(-\frac{7}{15}\right) = -\frac{27}{10}-\frac{5}{3}-\frac{2\times 2+1}{2}\left(1.4-\frac{1\times 5+4}{5}\right)-\left(-\frac{7}{15}\right) = -\frac{81}{30}-\frac{50}{30}-\frac{2\times 2+1}{2}\left(1.4-\frac{1\times 5+4}{5}\right)-\left(-\frac{7}{15}\right) = -\frac{131}{30}-\frac{5}{2}\left(1.4-\frac{1\times 5+4}{5}\right)-\left(-\frac{7}{15}\right) = -\frac{131}{30}-\frac{5}{2}\left(1.4-\frac{9}{5}\right)-\left(-\frac{7}{15}\right) = -\frac{131}{30}-\frac{5}{2}\left(\frac{7}{5}-\frac{9}{5}\right)-\left(-\frac{7}{15}\right) = -\frac{131}{30}-\frac{5}{2}\left(-\frac{2}{5}\right)-\left(-\frac{7}{15}\right) = -\frac{131}{30}-\frac{-2}{2}-\left(-\frac{7}{15}\right) = -\frac{131}{30}-\left(-1\right)-\left(-\frac{7}{15}\right) = -\frac{131}{30}+1-\left(-\frac{7}{15}\right) = -\frac{131}{30}+\frac{30}{30}-\left(-\frac{7}{15}\right) = -\frac{101}{30}-\left(-\frac{7}{15}\right) = -\frac{101}{30}+\frac{7}{15} = -\frac{101}{30}+\frac{14}{30} = \frac{-87}{30} = -\frac{29}{10} = -2 \frac{9}{10} [/tex]