[tex]dane:\\F = 120 \ N\\W = 90 \ J\\szukane:\\h = ?\\\\W = F\cdot h \ \ /:F\\\\h = \frac{W}{F}\\\\h = \frac{90 \ J}{120 \ N} = \frac{90 \ kg\cdot\frac{m^{2}}{s^{2}}}{120 \ kg\cdot\frac{m}{s^{2}}} = 0,75 \ m[/tex]
Odp. Ciało podniesiono na wysokosć h = 0,75 m.
