Odpowiedź :
a, b, c, e, g, h
a) C3H7COOH+C4H9OH--st. H2SO4--->C3H7COOC4H9+H2O
b) 6C2H5COOH+Al2O3--->2(C2H5COO)3Al+3H2O
c) C17H33COOH+Br2--->C17H34COOBr2
e) CH3COOH+KOH--->CH3COOK+H2O
g) 2K+2C17H35COOH--->2C17H35COOK+H2
h) 2Na+2C2H5COOH--->2C2H5COONa+H2