[tex]dane:\\m = 1000 \ kg\\F_{c} = 6 \ 000 \ N\\F_{T} = 1000 \ N\\F_{w} = F_{c}-F_{T} = 6000 \ N - 1000 \ N = 5 \ 000 \ N\\v = 20\frac{m}{s}\\szukane:\\t = ?\\\\Rozwiazanie\\\\a =\frac{F_{w}}{m}\\oraz\\a = \frac{v}{t}\\\\\frac{v}{t} = \frac{F_{w}}{m}\\\\F_{w}\cdot t = v\cdot m \ \ /:F_{w}\\\\t =\frac{v\cdot m}{F_{w}}\\\\t = \frac{20\frac{m}{s}\cdot1000 \ kg}{5000 \ N} = \frac{20 \ kg\cdot\frac{m}{s}}{5 \ kg\cdot\frac{m}{s^{2}}}\\\\t = 4 \ s[/tex]
