Odpowiedź :
[tex]dane:\\P = 270 \ kJ = 270 \ 000 \ J\\t = 3 \ min = 3\cdot60 \ s = 180 \ s\\szukane:\\P = ?\\\\P = \frac{W}{t}\\\\P = \frac{270000 \ J}{180 \ s} = 1 \ 500 \ W = 1,5 \ kW\approx 2 \ kW[/tex]
[tex]dane:\\P = 270 \ kJ = 270 \ 000 \ J\\t = 3 \ min = 3\cdot60 \ s = 180 \ s\\szukane:\\P = ?\\\\P = \frac{W}{t}\\\\P = \frac{270000 \ J}{180 \ s} = 1 \ 500 \ W = 1,5 \ kW\approx 2 \ kW[/tex]