BLAGAM NIECH KTOS POMOZE TWIERDZENIE PITAGORASA

Odpowiedź:
[tex](5 \sqrt{5) ^{2} } = 2 {}^{2} + \times {}^{2} [/tex]
[tex]25 \times 5 = 4 + \times {}^{2} [/tex]
[tex]125 = 4 + \times {}^{2} [/tex]
[tex] \times {}^{2} = 125 - 4 = 121[/tex]
[tex] \times {}^{2} = \sqrt{121} = 11[/tex]