[tex]dane:\\m = 250 \ g = 0,25 \ kg\\h = 10 \ m\\v = 30\frac{m}{s}\\g = 10\frac{m}{s^{2}}\\szukane:\\E_{m} = ?\\\\Rozwiazanie\\\\E_{m} = E_{p} + E_{k}\\\\E_{p} = mgh\\\\E_{k} = \frac{mv^{2}}{2}\\\\E_{p} = 0,25 \ kg \cdot10\frac{m}{s^{2}}\cdot10 \ m=25 \ J\\\\E_{k} = \frac{0,25 \ kg\cdot(30\frac{m}{s})^{2}}{2} = 112,5 \ J\\\\E_{m} = 25 \ J + 112,5 \ J = 137,5 \ J\\\\Odp. \ a)[/tex]
