Odpowiedź :
[tex]dane:\\W = 30 \ 000 \ J\\t = 15 \ s\\szukane:\\P = ?\\\\P = \frac{W}{t}\\\\P = \frac{30 \ 000 \ J}{15 \ s}\\\\P = 2 \ 000 \ W = 2 \ kW[/tex]
[tex]dane:\\W = 30 \ 000 \ J\\t = 15 \ s\\szukane:\\P = ?\\\\P = \frac{W}{t}\\\\P = \frac{30 \ 000 \ J}{15 \ s}\\\\P = 2 \ 000 \ W = 2 \ kW[/tex]