ROZWIĄZ RÓWNANIE
a 2[5a - 3] - a - 4 [3a - 2] = 0
b 2b- [1-b] = 11-b
c2/5[ x-2]=x+4
d 3y - 2[y-1] =6
e 3[3-5y 2 do kwadratu] = 90 - 5[3y 2 do kwadratu - 2y}
f 1/4z + [z-6] = 2/3 [z-2]
g 5[2-3x do kwadratu] =3[2-5x kwadrat] + x
h 0,6 [1- z] = 0.3[8-x]