[tex]dane:\\m = 90 \ kg\\E_{p} = 10 \ kJ = 10 \ 000 \ J\\g = 10\frac{N}{kg}\\szukane:\\h = ?\\\\Rozwiazanie\\\\E_{p} = mgh \ \ /:mg\\\\h = \frac{E_{p}}{mg}\\\\h = \frac{10000 \ J}{90 \ kg\cdot10\frac{N}{kg}} = \frac{10000 \ N\cdot m}{900\cdot \ N}}=11,1 \ m[/tex]
