Odpowiedź :
[tex]dane:\\t = 15 \ min = \frac{15}{60} \ h = \frac{1}{4} \ h\\v = 90\frac{km}{h}\\szukane:\\s = ?\\\\s = v\cdot t\\\\s = 90\frac{km}{h}\cdot\frac{1}{4} \ h\\\\s = 22,5 \ km[/tex]
[tex]dane:\\t = 15 \ min = \frac{15}{60} \ h = \frac{1}{4} \ h\\v = 90\frac{km}{h}\\szukane:\\s = ?\\\\s = v\cdot t\\\\s = 90\frac{km}{h}\cdot\frac{1}{4} \ h\\\\s = 22,5 \ km[/tex]