Odpowiedź :
zad.1
mr= 140 g
mNaCl= 20 g
Cp=(mNaCl÷mr)*100%
Cp= (20 g÷140 g) *100%=14,29%
Zad 2
mNaCl= 20 g
mH2O= 140 g
mr= mNaCl + mH2O= 20 g + 140 g= 160 g
Cp=(mNaCl÷mr)*100%
Cp= ( 20 g÷160 g)*100%= 12,5%
zad.1
mr= 140 g
mNaCl= 20 g
Cp=(mNaCl÷mr)*100%
Cp= (20 g÷140 g) *100%=14,29%
Zad 2
mNaCl= 20 g
mH2O= 140 g
mr= mNaCl + mH2O= 20 g + 140 g= 160 g
Cp=(mNaCl÷mr)*100%
Cp= ( 20 g÷160 g)*100%= 12,5%