Odpowiedź :
1.
CaCO3
Ca = 40u
C = 12u
O3 = 16*3=48u
40u+12u+48u= 90u
40:12:48
10:3:12
2.
P4O10
P4= 31u*4= 124u
O10= 16*10=160u
mP4O10=184u
(160u*100%)/184u=86,9565217~87%
1.
CaCO3
Ca = 40u
C = 12u
O3 = 16*3=48u
40u+12u+48u= 90u
40:12:48
10:3:12
2.
P4O10
P4= 31u*4= 124u
O10= 16*10=160u
mP4O10=184u
(160u*100%)/184u=86,9565217~87%