Zadanie 1
C3H7COOH+C2H5OH--st. H2SO4--->C3H7COOC2H5+H2O
maślan etylu
Zadanie 2
mC3H7COOC2H5=6*12u+12*1u+2*16u=116u
72u---x%
116u---100%
x=62,07%C
12u---x%
116u---100%
x=10,34%H
100%-(62,07%+10,34%)=27,59%O
Zadanie 3
stosunek atomowy:
C:H:O=6:12:2=3:6:1
Stosunek masowy:
mC:mH:mO=72:12:32=18:3:8