Odpowiedź :
[tex]a) \\3^2+6^2=d^2\\9+36=d^2\\d = \sqrt{45} = 3\sqrt{5}\\\\b) \\a = \sqrt{19} \\d = a\sqrt{2}\\d = \sqrt{19*2} = \sqrt{38}[/tex]
[tex]a) \\3^2+6^2=d^2\\9+36=d^2\\d = \sqrt{45} = 3\sqrt{5}\\\\b) \\a = \sqrt{19} \\d = a\sqrt{2}\\d = \sqrt{19*2} = \sqrt{38}[/tex]