[tex]Zadanie\\\\a=6\\h=8\\\\P_p=6\cdot\frac{a^2\sqrt{3} }{4}\\\\P_p= 6\cdot\frac{6^2 \cdot\sqrt{3} }{4} = 6\cdot\frac{36\sqrt{3} }{4}=6\cdot9\sqrt{3} =54\sqrt{3}\ (j^2)\\\\\\ V=\frac{1}{3}\cdot P_p\cdot h \\\\V=\frac{1}{3}\cdot54\sqrt{3}\cdot8= 18\sqrt{3}\cdot8=144\sqrt{3}\ (j^3)[/tex]
