5.
[tex]dane:\\\Delta T = 5^{o}C\\Q = 1000 \ J\\m = 2 kg\\szukane:\\c_{w} = ?\\\\Rozwiazanie\\\\c_{w} = \frac{Q}{m\cdot \Delta T}\\\\c_{w} = \frac{1000 \ J}{2 \ kg\cdot 5^{o}C}\\\\c_{w} = 100\frac{J}{kg\cdot^{o}C}[/tex]
6.
[tex]dane:\\m = 0,5 \ kg\\Q = 260 \ J\\c_{w} = 130\frac{J}{kg\cdot^{o}C}\\szukane:\\\Delta T = ?\\\\Rozwiazanie\\\\Q = c_{w}\cdot m\cdot \Delta T \ \ /:(c_{w}\cdot m)\\\\\Delta T = \frac{Q}{c_{w}\cdot m}\\\\\Delta T = \frac{260 \ J}{130\frac{J}{kg\cdot^{o}C}\cdot0,5 \ kg}\\\\\Delta T = 4^{o}C[/tex]
