Odpowiedź:
[tex]a) \frac{3}{9} , \frac{3}{13}\\\\b) 3\frac{6}{7}, 3\frac{1}{5}\\\\c) \frac{2}{3}, 0[/tex]
Szczegółowe wyjaśnienie:
[tex]a) \\\frac{2}{9} + \frac{1}{9} = \frac{3}{9}\\\frac{8}{13} - \frac{5}{13} = \frac{3}{13}\\\\\\b)\\\frac{25}{7} + \frac{2}{7} = \frac{27}{7}= 3\frac{6}{7} \\\frac{23}{5} - \frac{7}{5} = \frac{16}{5} = 3\frac{1}{5}\\\\c)\\0 + \frac{2}{3} = \frac{2}{3}\\\frac{15}{32}-\frac{15}{32} = 0[/tex]
