Odpowiedź :
zad 1.
[tex]\frac{k}{29} =40 => k=40*29=1160[/tex]
zad.2
87=2x-5 => 2x=92 => x=46
zad.3
[tex]\frac{1}{4}(4x-8)=3-x => x-2=3-x => 2x=5 => x=2\frac{1}{2}[/tex]
zad 1.
[tex]\frac{k}{29} =40 => k=40*29=1160[/tex]
zad.2
87=2x-5 => 2x=92 => x=46
zad.3
[tex]\frac{1}{4}(4x-8)=3-x => x-2=3-x => 2x=5 => x=2\frac{1}{2}[/tex]