Odpowiedź:
[tex]a) -1,2*(x+4)=0,8*(x-4)+2,4\\-1,2x-4,8=0,8x-3,2+2,4\\-1,2x-4,8=0,8x -0,8\\-1,2x-0,8x=-0,8+4,8\\-2x=4\\x=-2\\[/tex]
[tex]Spr.:-1,2*(-2+4)=0,8*(-2-4)+2,4\\-1,2*2=0,8*(-6)+2,4\\-2,4=-4,8+2,4\\-2,4=-2,4 \\L=P[/tex]
[tex]b) \frac{x-15}{5} +0,8x=5\\\frac{x-15}{5} +\frac{4}{5}x=5\\x-15+4x=25\\5x-15=25\\5x=25+15\\5x=40\\x=8\\[/tex]
[tex]Spr.:\frac{8-15}{5} +0,8*8=5\\\\frac{-7}{5} +6,4=5\\\\frac{-7}{5} +\frac{32}{5} =5\\\\frac{25}{5} =5\\5=5\\L=P[/tex]
[tex]c) \frac{x-1}{2} +x=\frac{x+2}{2} -4\\x-1+2x=x+2-8\\-1+2x=2-8\\-1+2x=-6\\2x=-6+1\\2x=-5\\x=-\frac{5}{2} = -2\frac{1}{2}[/tex]
[tex]Spr.:\frac{-2\frac{1}{2} -1}{2} +(-2\frac{1}{2}) =\frac{-2\frac{1}{2}+2 }{2}-4 \\\frac{-3\frac{1}{2} }{2} -2\frac{1}{2} =\frac{-\frac{5}{2}+2 }{2} -4\\\frac{-\frac{7}{2} }{2} -\frac{5}{2} =\frac{-\frac{1}{2} }{2} -4\\-\frac{\frac{7}{2} }{2}-\frac{5}{2} =-\frac{\frac{1}{2} }{2} -4\\-\frac{7}{4} -\frac{5}{2} =-\frac{1}{4} -4\\-\frac{17}{4} =-\frac{17}{4} \\L=P[/tex]
[tex]d) 0,2x-\frac{1}{5} *(x+1)=x(x-2)-8,2-x^{2} \\\frac{1}{5} x-\frac{1}{5} x-\frac{1}{5}=x^{2} -2x-8,2-x^{2} \\-\frac{1}{5} =-2x-\frac{41}{5} \\-1=-10x-41\\10x=-41+1\\10x=-40\\x=-4[/tex]
[tex]Spr.:0,2*(-4)-\frac{1}{5} *(-4+1)=-4(-4-2)-8,2-(-4)^{2} \\-0,8-\frac{1}{5} *(-3)=-4*(-6)-8,2-16\\-\frac{4}{5} +\frac{3}{5} =24-8,2-16\\-\frac{1}{5} =-0,2\\-0,2=-0,2\\L=P[/tex]
[tex]e) x+\frac{2x+1}{4} =\frac{x}{2} +\frac{3}{4} \\4x+2x+1=2x+3\\4x+1=3\\4x=3-1\\4x=2\\x=\frac{1}{2}[/tex]
[tex]Spr.:\frac{1}{2} +\frac{2*\frac{1}{2}+1 }{4} =\frac{\frac{1}{2} }{2} +\frac{3}{4} \\\frac{1}{2} +\frac{1+1}{4} =\frac{1}{4} +\frac{3}{4} \\\frac{1}{2} +\frac{2}{4} =1\\1=1\\L=P[/tex]
[tex]f) \frac{x-1}{3} -\frac{x+2}{2} =x-\frac{1}{6} \\2(x-1)-3(x+2)=6x-1\\2x-2-3x-6=6x-1\\-x-8=6x-1\\-x-6x=-1+8\\-7x=7\\-x=1\\x=-1[/tex]
[tex]Spr.:\frac{-1-1}{3} -\frac{-1+2}{2} =-1-\frac{1}{6} \\\frac{-2}{3} -\frac{1}{2} =-\frac{7}{6} \\-\frac{7}{6} =-\frac{7}{6} \\L=P[/tex]
Mam nadzieję, że pomogłam :)
Liczę na najj ♥
