Odpowiedź :
[tex]Zadanie\\\\sin^2\alpha+cos^2\alpha=1\\\\sin\alpha\cdot \cos\alpha=\frac{1}{5}\\\\(sin\alpha+cos\alpha)^2=sin^2\alpha+cos^2\alpha+2sin\alpha\cdot\cos\alpha= 1+2\cdot\frac{1}{5}=1+\frac{2}{5}=1\frac{2}{5}[/tex]
[tex]Zadanie\\\\sin^2\alpha+cos^2\alpha=1\\\\sin\alpha\cdot \cos\alpha=\frac{1}{5}\\\\(sin\alpha+cos\alpha)^2=sin^2\alpha+cos^2\alpha+2sin\alpha\cdot\cos\alpha= 1+2\cdot\frac{1}{5}=1+\frac{2}{5}=1\frac{2}{5}[/tex]