Te dwa przykłady z matematyki do wykonania, 1 technikum.

Odpowiedź:
[tex]\left \{ {{2x-3y=5/*(2} \atop {6y-5x=-8}} \right.[/tex]
[tex]\left \{ {{4x-6y=10} \atop {-5x+6y=-8}} \right.[/tex]
--------------------
-x=2/:(-1)
x=-2
2*(-2)-3y=5
-3y=5+4
-3y=9/:(-3)
y= -3
(x,y)=(-2,-3)
[tex]\left \{ {{\frac{2x-y}{3}=\frac{3x+y}{2}} \atop {x=2(x+y+1)}} \right.[/tex]
[tex]\left \{ {{4x-2y=9x+3y} \atop {x=2x+2y+2}} \right.[/tex]
[tex]\left \{ {{4x-9x=3y+2y} \atop {x-2x-2y=2}} \right.[/tex]
[tex]\left \{ {{-5x-5y=0} \atop {-x-2y=2/*(-5)}} \right.[/tex]
[tex]\left \{ {{-5x-5y=0} \atop {5x+10y=-10}} \right.[/tex]
-------------------
5y=-10/:5
y=-2
x=2(x+(-2)+1)
x=2x-4+2
x-2x=-2
-x=-2/:(-1)
x=2
x,y=(2,-2)
Szczegółowe wyjaśnienie: