[tex]Zadanie\ 11\\\\a)\\\\3\frac{3}{8}-\frac{5}{8}= 2\frac{11}{8}-\frac{5}{8}=2\frac{6}{8}=2 \frac{3}{4}\\\\b)\\\\5\frac{5}{8}- \frac{7}{8}=4\frac{13}{8}-\frac{7}{8}=4\frac{6}{8}= 4\frac{3}{4}\\\\c)\\\\7\frac{3}{5}- \frac{4}{5}=6\frac{8}{5}- \frac{4}{5}=6 \frac{4}{5}\\\\ d) \\\\6\frac{5}{9}- \frac{8}{9}=5\frac{14}{9}- \frac{8}{9}=5\frac{6}{9}= 5\frac{2}{3}[/tex]
