[tex]a)\\\\\frac{x}{3}+1= \frac{5}{6}+ \frac{x}{2}\ \ |*6\\\\2x+6=5+3x\\\\2x-3x=5-6\\\\-x=-1\ \ |*(-1)\\\\x=1[/tex]
[tex]b)\\\\ \frac{ 2x+3}{5} =\frac{ 2-x}{3} + x\ \ |*15\\\\3(2x+3)=5(2-x)+15x\\\\6x+9=10-5x+15x\\\\6x+9=10+10x\\\\6x-10x=10-9\\\\-4x=1\ \ ::(-4)\\\\x=-\frac{1}{4}[/tex]
[tex]c)\\\\ \frac{2}{5}(3-x)=-2\ \ |*5\\\\2(3-x)=-10\\\\6-2x=-10\\\\-2x=-10-6\\\\-2x=-16\ \ |:(-2)\\\\x=8[/tex]
[tex]d)\\\\ \frac{3x-5 }{2} - \frac{ 5x-1}{10} =0\ \ |*10\\\\5(3x-5)-(5x-1)=0\\\\15x-25-5x+1=0\\\\10x-24=0\\\\10x=24\ \ |:10\\\\x=\frac{24}{10}=\frac{12}{5}=2\frac{2}{5}[/tex]
[tex]e)\\\\1- \frac{6}{7}x= \frac{4}{7}\\\\-\frac{6}{7}x=\frac{4}{7}-1\\\\-\frac{6}{7}x=-\frac{3}{7}\ \ |*(-\frac{7}{6})\\\\x=\frac{1}{2}[/tex]
