Odpowiedź :
[tex]h = 25 \ cm = 0,25 \ m\\d = 800\frac{kg}{m^{3}}\\g = 10\frac{N}{kg}\\p = ?\\\\p = d\cdot g\cdot h\\\\p = 800\frac{kg}{m^{3}}\cdot10\frac{N}{kg}\cdot0,25 \ m\\\\p = 2 \ 000 \ Pa = 20 \ hPa = 2 \ kPa[/tex]
[tex]h = 25 \ cm = 0,25 \ m\\d = 800\frac{kg}{m^{3}}\\g = 10\frac{N}{kg}\\p = ?\\\\p = d\cdot g\cdot h\\\\p = 800\frac{kg}{m^{3}}\cdot10\frac{N}{kg}\cdot0,25 \ m\\\\p = 2 \ 000 \ Pa = 20 \ hPa = 2 \ kPa[/tex]