a)
suma miar kątów w trójkacie = 180
180= 90+60 + β
β=30
c= 4√3
b= 4√3√3/2 = 12/2 = 6
b)
β= 60
a= 4√2/2 = 2√2
b= 4√2√3 /2 = 4√6/2= 2√6
c)
β= 30
( wzór: h=a√3/2 => 2h = a√3 => 2h√3/3 = a)
c = 18√3/3 = 9√3
a= c/2 = 4,5√3
d)
β= 60
a= √6/2 /2 = √6/4
b= √6/2*√3 /2 = √18/4= 3√2/4
