Matemtyka potęgi zad w załączniku

[tex](-5x^{2} )^3 = -125x^6\\6^6*6^2:6^3 = 6^5\\-10^0=-1\\(\frac{16}{9} )^2*(\frac{18}{4} )^2= (\frac{16}{9} *\frac{18}{4} )^2= 8^2=64\\((3^6)^2)^2:3^{14} =3^{10}\\(4^2)^3*4^2:4^3=4^5=1024\\\frac{5^{23} }{25} = \frac{5^{23} }{5^{2} } =5^{21} \\-(-3)^3=-(-27)=27\\\frac{2^{3} }{8^{2} } =\frac{2^{3} }{2^{6} } =2^{-3} \\(2^{16} *8)^2=(2^{16}*2^3)^2=(2^{19})^2=2^{38}[/tex]