Odpowiedź:
[tex] {5}^{2} + {12}^{2} = {b}^{2} \\ 25 + 144 = {b}^{2} \\ {b}^{2} = \sqrt{169} \\ b = 13 \\ \\ \\ {6}^{2} + {10}^{2} = {d}^{2} \\ 36 + 100 = {d}^{2} \\ {d}^{2} = \sqrt{136} \\ d = 2 \sqrt{34} \\ \\ \\f + \sqrt{6 { }^{2} } = \sqrt{10^{2} } \\ f + 6 = 10 \\ f = 10 - 6 \\ f = 4[/tex]
