Proszę wykonanie tylko zadań C, H

Odpowiedź:
c)
[tex]2 \frac{2}{7} + 1 \frac{1}{3} = 2 \frac{6}{21} + 1 \frac{7}{21} = 3 \frac{13}{21} [/tex]
[tex] - 4 \frac{1}{4} + \frac{3}{14} = - 4 \frac{7}{28} + \frac{6}{28} = - 4 \frac{1}{28} [/tex]
[tex]10 \frac{1}{4} +2 \frac{3}{18} = 10 \frac{1}{4} + 2 \frac{1}{6} = 10 \frac{3}{12} + 2 \frac{2}{12} = 12 \frac{5}{12} [/tex]
[tex]6 \frac{1}{5} + 7 \frac{7}{8} = 6 \frac{8}{40} + 7 \frac{35}{40} = 13 \frac{43}{40} = 14 \frac{3}{40} [/tex]
[tex]8 \frac{2}{3} + 6 \frac{3}{10} = 8 \frac{20}{30} + 6 \frac{9}{30} = 14 \frac{29}{30} [/tex]
[tex]9 \frac{7}{15} + 1 \frac{7}{12} = 9 \frac{28}{60} + 1 \frac{35}{60} = 10 \frac{63}{60} = 11 \frac{3}{60} = 11 \frac{1}{20} [/tex]
h)
[tex]3 \frac{1}{12} - \frac{5}{8} = 3 \frac{2}{24} - \frac{15}{24} = 2 \frac{26}{24} - \frac{15}{24} = 2 \frac{11}{24} [/tex]
[tex]8 \frac{3}{4} - 4 \frac{5}{6} = 8 \frac{9}{12} - 4 \frac{10}{12} = 7 \frac{21}{12} - 4 \frac{10}{12} = 3 \frac{11}{12} [/tex]
[tex]10 \frac{2}{5} - 3 \frac{5}{6} = 10 \frac{12}{30} - 3 \frac{25}{30} = 9 \frac{42}{30} - 3 \frac{25}{30} = 6 \frac{17}{30} [/tex]
[tex]12 \frac{2}{5} - 1 \frac{2}{3} = 12 \frac{6}{15} - 1 \frac{10}{15} = 11 \frac{21}{15} - 1 \frac{10}{15} = 10 \frac{11}{15} [/tex]
[tex]14 \frac{1}{8} - 2 \frac{1}{3} = 14 \frac{3}{24} - 2 \frac{8}{24} = 13 \frac{27}{24} - 2 \frac{8}{24} = 11 \frac{19}{24} [/tex]
[tex]24 \frac{3}{10} - 11 \frac{5}{6 } = 24 \frac{9}{30} - 11 \frac{25}{30} = 23 \frac{39}{30} - 11 \frac{25}{30} = 12 \frac{14}{30} = 12 \frac{7}{15} [/tex]