Odpowiedź :
[tex]2x^{2} + 2x - 24 = 0\\\\a = 2, \:\;\;\;\;\; b = 2, \;\;\;\;\;\;\;c = -24\\\\[/tex]
Δ = b² - 4ac
Δ = 2² - 4*2 * (-24) =
Δ = 4 - 8 * + 24 =
Δ = 4 + 192 =
Δ = 196
[tex]x_{1} = \frac{-b-\sqrt{delty} }{2a} = \frac{-2-\sqrt{196} }{2*2} = \frac{-2-14}{4} = \frac{-16}{4} = -4[/tex]
[tex]x_{2} = \frac{-b + \sqrt{delty} }{2a} = \frac{-2+\sqrt{196} }{2*2} = \frac{-2 + 14}{4} = \frac{12}{4} = 3[/tex]
Odp: D