7.Przedstaw w postaci jednej potegi.

Odpowiedź:
a) 3^4 * 9^2 =
= 3^4 * (3^2)^2=
=3^4 * 3^4=
= 3^8
b)4^5*8^3=
=(2^2)^5 * (2^3)^3=
= 2^10 * 2^9=
=2^19
c) 8^3/ 2^5 =
= (2^3)^3/2^5=
=2^9/2^5=
=2^4
d)125^7/ 25^10 =
=(5^3)^7 / (5^2)^10=
=5^21/ 5^20=
=5
e) (1/9)^4/ (1/3)^3=
=(3^-2)^4/(3^-1)^3=
=3^-8/3^-3=
=3^ -5
f) 0,5^9/ (1/4)^4=
=(2^-1)^9/(2^-2)^4=
=2^-9 / 2^-8=
=2^-1
g) 0,1^9 / 0,001^2=
=10^-9/10^-6=
=10^-3
h) 5^8/ 32 * 2^10/ 125=
=5^8/2^5 * 2^10 / 5^3=
= 5^5 * 2^5=
= 10^5
Szczegółowe wyjaśnienie: