[tex]dane:\\r_1 = 0,5 \ m\\m_1 = 50 \ kg\\r_2 = 2 \ m\\g = 10\frac{N}{kg}\\szukane:\\P = F_1 = ?\\F = F_2 = ?\\\\Rozwiazanie\\\\F = m\cdot g\\\\P = F_1\\\\P = m_1\cdot g\\\\P = 50 \ kg\cdot10\frac{N}{kg}\\\\P = 500 \ N\\------[/tex]
Dźwignia dwustronna jest w równowadze, gdy:
[tex]r_1 \cdot F_1 = r_2\cdot F_2\\\\F_1 = P, \ \ F_2 = F\\\\r_1\cdot P = r_2\cdot F \ \ /:r_2\\\\F = P\cdot\frac{r_1}{r_2}\\\\F = 500 \ N\cdot\frac{0,5 \ m}{2 \ m} = 500 \ N\cdot0,25\\\\F = 125 \ N\\------[/tex]
