Odpowiedź :
[tex]Zadanie\\\\x_S=\frac{x_C+x_D}{2}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ y_S=\frac{y_C+y_D}{2}\\\\x_S=\frac{2+4}{2}=\frac{6}{2}=3\ \ \ \ \ \ \ \ \ \ \ y_S=\frac{7+(-5)}{2}=\frac{2}{2}=1 \\\\S=(3,1)[/tex]
[tex]Zadanie\\\\x_S=\frac{x_C+x_D}{2}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ y_S=\frac{y_C+y_D}{2}\\\\x_S=\frac{2+4}{2}=\frac{6}{2}=3\ \ \ \ \ \ \ \ \ \ \ y_S=\frac{7+(-5)}{2}=\frac{2}{2}=1 \\\\S=(3,1)[/tex]