Odpowiedź :
Zadanie 5
[tex]\frac{-25 + (-20) + 15}{3} = \frac{-25 - 20 + 15}{3}= \frac{-30}{3} = -10[/tex]
Zadanie 6
a) -7°C - (-10°C) = -7°C + 10°C = -3°C
b) -3°C - 4°C = -7°C
c) 2°C - 5°C = -3°C
Zadanie 5
[tex]\frac{-25 + (-20) + 15}{3} = \frac{-25 - 20 + 15}{3}= \frac{-30}{3} = -10[/tex]
Zadanie 6
a) -7°C - (-10°C) = -7°C + 10°C = -3°C
b) -3°C - 4°C = -7°C
c) 2°C - 5°C = -3°C