Odpowiedź :
m= 20 kg
L=6 m
α=60°
g=10 m/s²
μ=?
R-T=0
N-Fc=0
N=Fc=m*g
R=N*μ
R=m*g*μ
Równania momentów
R*L*sin(α)=Fn*0,5*L
Fn=Fc*cos(α)
m*g*μ*L*sin(α)=Fn*0,5*L
m*g*μ*L*sin(α)=m*g*cos(α)*0,5*L
μ*L*sin(α)=cos(α)*0,5*L
μ=(cos(α))/(2*sin(α))
μ=1/(2*tan(α))
μ ≈ 0,3
