Liczba log. POMOCY!!!

[tex]\frac{2log100+log_{7}49}{log_{4}64 + log_{2}1} = \frac{2log10^{2}+log_{7}7^{2}}{log_{4}4^{3}+log_{2}2^{0}}=\frac{2\cdot2+2}{3+0} = \frac{6}{3} = 2\\\\Odp. \ B.[/tex]