a)
[tex]1\frac{3}{4}+2\frac{3}{4}+3\frac{3}{4}=(1+2+3)+(\frac{3}{4}+\frac{3}{4}+\frac{3}{4})=6+\frac{9}{4}=6+2\frac{1}{4}=6+2+\frac{1}{4}=8\frac{1}{4}[/tex]
b)
[tex]2\frac{3}{8}+9\frac{5}{8}+1\frac{7}{8}=(2+9+1)+(\frac{3}{8}+\frac{5}{8}+\frac{7}{8})=12+\frac{15}{8}=12+1\frac{7}{8}=12+1+\frac{7}{8}=13\frac{7}{8}[/tex]
c)
[tex]9\frac{7}{10}+7\frac{5}{10}+\frac{9}{10}=\frac{97}{10}+\frac{75}{10}+\frac{9}{10}=\frac{181}{10}=18\frac{1}{10}[/tex]
d)
[tex]\frac{5}{12}+3\frac{8}{12}+5\frac{11}{12} =\frac{5}{12}+\frac{44}{12}+\frac{71}{12}=10[/tex]
