Odpowiedź :
6.
[tex]7(x-6)-4(9x-7) = 7x-42 - 36x+28 = -29x -14\\\\(9c^{2}+12b^{2}+15):3 = 3(3c^{2}+4b^{2}+5):3 = 3c^{2}+4b^{2}+5[/tex]
6.
[tex]7(x-6)-4(9x-7) = 7x-42 - 36x+28 = -29x -14\\\\(9c^{2}+12b^{2}+15):3 = 3(3c^{2}+4b^{2}+5):3 = 3c^{2}+4b^{2}+5[/tex]