Odpowiedź :
[tex]a_{n} = 2n-1[/tex]
[tex]a_1 = 2\cdot1 - 1 = 2-1 = 1\\\\a_2 = 2\cdot2 -1 = 4-1 = 3\\\\a_3 = 2\cdot3 - 1 = 6-1 = 5\\\\a_4 = 2\cdot4 - 1 = 8-1 = 7\\\\a_5 = 2\cdot5-1 = 10-1 = 9[/tex]
[tex]a_{n} = 2n-1[/tex]
[tex]a_1 = 2\cdot1 - 1 = 2-1 = 1\\\\a_2 = 2\cdot2 -1 = 4-1 = 3\\\\a_3 = 2\cdot3 - 1 = 6-1 = 5\\\\a_4 = 2\cdot4 - 1 = 8-1 = 7\\\\a_5 = 2\cdot5-1 = 10-1 = 9[/tex]