Odpowiedź :
[tex]\frac{2sin\alpha+3cos\alpha}{cos\alpha}=8\\\\\frac{2sin\alpha}{cos\alpha}+\frac{3cos\alpha}{cos\alpha}=8\\\\2tg\alpha+3=8\\\\2tg\alpha=8-3\\\\2tg\alpha=5\ \ \ \ |:2\\\\tg\alpha=2,5[/tex]
[tex]\frac{2sin\alpha+3cos\alpha}{cos\alpha}=8\\\\\frac{2sin\alpha}{cos\alpha}+\frac{3cos\alpha}{cos\alpha}=8\\\\2tg\alpha+3=8\\\\2tg\alpha=8-3\\\\2tg\alpha=5\ \ \ \ |:2\\\\tg\alpha=2,5[/tex]