Odpowiedź :
[tex]2\sqrt[3]{16} +5\sqrt[3]{54} =2\sqrt[3]{8\cdot2} +5\sqrt[3]{27\cdot2} =2\cdot2\sqrt[3]{2} +5\cdot3\sqrt[3]{2} =4\sqrt[3]{2} +15\sqrt[3]{2} =19\sqrt[3]{2}[/tex]
[tex]\sqrt{32}+\sqrt{72}+\sqrt{50}=\sqrt{16\cdot2}+\sqrt{36\cdot2}+\sqrt{25\cdot2}=4\sqrt{2}+6\sqrt{2}+5\sqrt{2}=15\sqrt2[/tex]
[tex]\sqrt{12}+\sqrt{75}+\sqrt{24}-\sqrt{96}=\sqrt{4\cdot3}+\sqrt{25\cdot3}+\sqrt{4\cdot6}-\sqrt{16\cdot6}=\\2\sqrt{3}+5\sqrt{3}+2\sqrt{6}-4\sqrt6}=7\sqrt{3}-2\sqrt{6}[/tex]