Odpowiedź:
a)
[tex]32 {}^{x} = 8 \\ ((2) {}^{5} ) { }^{x} = ( 2){}^{2} \\ (2) {}^{5x} = (2) {}^{3} \\ 5x = 3 \\ x = \frac{3}{5} [/tex]
d)
[tex]32 {}^{x - 4} \times \sqrt{8 } = \frac{ {16}^{x} }{4 \sqrt{2} } \\ ((2) {}^{5} ) {}^{x - 4} \times \sqrt{8} \times 4 \sqrt{2} = {16}^{x} \\ ((2) {}^{5} ) {}^{x - 4} \times16 = {16}^{x} \\ ((2) {}^{5} ) {}^{x - 4} \times {2}^{4} = {2}^{4x} \\ (((2) {}^{5} ) {}^{x - 4}) {}^{4} = {2}^{4x} \\ 20(x - 4) = 4x \\ 20x - 80 = 4x \\ - 80 = - 16x \\ x = 5[/tex]
