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zadanie 13 str 223
wiedziąc ze 2do potengi 10= 1024 oblicz
(-2) do potengi 10
-2 do potengi 10
(-1/2) do potengi 10
- 0,5 do potengi 10
(-0,5) do potegi 10
2 do potęgi 11
2 do potengi 9


Odpowiedź :

(-2)^ 10 = 2^10 = 1024
-2^ 10 = -1024
(-1/2)^10 = (1/2)^10 = 1^10/2^10 = 1/1024
-0,5^10 = -(1/2)^10 = - 1/1024
(-0,5)^10 = (-1/2)^10= 1/1024
2^11 = 2048
2^9 = 512
( ^ - oznacza do potęgi)