Prosze to zadanie daje najjjjj

[tex]3x * 12 = 36x\\\\4 * 0,7x = 2,8x\\\\\frac{1}{3} * 6x = 2x\\\\\frac{1}{2} * \frac{1}{3}x = \frac{1}{6} x\\\\2y * (-\frac{3}{4}) = -\frac{3}{2y} \\\\\frac{x}{2} * 6 = 3x\\\\6x : 3 = 2x\\\\\frac{3}{4}x : 2 = \frac{3}{8}x\\\\\frac{15x}{3} = 5x\\\\6 * \frac{x}{9} = \frac{2x}{3\\}\\\\\frac{2,5x}{0,5} = 5x\\\\\frac{x}{3} * (-9) = -3x[/tex]
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