[tex]Zadanie\\\\A)\\\\4(2x+4)=10\\\\8x+16=10\ \ \ \mid-16\\\\8x =-6\ \ \ \mid:8\\\\x=-\frac{6}{8}\\\\x=-\frac{3}{4}\\\\B)\\\\5x+6=-12-8\\\\5x+6=-20\ \ \ \mid-6\\\\5x=-26\ \ \ \mid:5\\\\x=-\frac{26}{5}\\\\x=-5\frac{1}{5}[/tex]
[tex]C)\\\\\frac{3x-1}{2} +\frac{x+2}{2}=8\ \ \ \mid\cdot2\\\\3x-1+x+2=16\\\\4x+1=16\ \ \ \mid-1\\\\4x=15\ \ \ \mid:4\\\\x=\frac{15}{4}\\\\x=3\frac{3}{4}[/tex]
