Odpowiedź :
Odpowiedź:
[tex]CaCl_2\\mCa : 40u\\mCl : 2* 35 u = 70u\\40u + 70u = 110u\\\\\frac{40}{110} = 0,3636...[/tex]
%Ca = 36,36%
[tex]\frac{70}{110} = 0,63636...[/tex]
%Cl = 63,64%
Odpowiedź:
[tex]CaCl_2\\mCa : 40u\\mCl : 2* 35 u = 70u\\40u + 70u = 110u\\\\\frac{40}{110} = 0,3636...[/tex]
%Ca = 36,36%
[tex]\frac{70}{110} = 0,63636...[/tex]
%Cl = 63,64%