Cześć ;-)
Od a) do d)
[tex]2\dfrac{1}{3}=\dfrac{2\cdot3+1}{3}=\dfrac{6+1}{3}=\dfrac{7}{3}\\\\\\3\dfrac{1}{2}=\dfrac{3\cdot2+1}{2}=\dfrac{6+1}{2}=\dfrac{7}{2}\\\\\\2\dfrac{3}{8}=\dfrac{2\cdot8+3}{8}=\dfrac{16+3}{8}=\dfrac{19}{8}\\\\\\6\dfrac{2}{3}=\dfrac{6\cdot3+2}{3}=\dfrac{18+2}{3}=\dfrac{20}{3}[/tex]
Od e) do h)
[tex]3\dfrac{3}{5}=\dfrac{3\cdot5+3}{5}=\dfrac{15+3}{5}=\dfrac{18}{5}\\\\\\2\dfrac{7}{9}=\dfrac{2\cdot9+7}{9}=\dfrac{18+7}{9}=\dfrac{25}{9}\\\\\\9\dfrac{3}{4}=\dfrac{9\cdot4+3}{4}=\dfrac{36+3}{4}=\dfrac{39}{4}\\\\\\10\dfrac{1}{6}=\dfrac{10\cdot6+1}{6}=\dfrac{60+1}{6}=\dfrac{61}{6}[/tex]
Pozdrawiam!
